document.write( "Question 1192754: A team of five is to be chosen from four men and five women to work on a special project
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document.write( " i. In how many ways can the team be chosen?
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document.write( " ii. In how many ways can the team be chosen to include just three women?
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document.write( " iii. What is the probability that the team just includes three women?
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document.write( " iv. What is the probability that the team include at least three women?
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document.write( "v. What is the probability that the team includes more men than women
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Algebra.Com's Answer #824698 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 9C5 ways to choose the groups=126 ways \n" ); document.write( "- \n" ); document.write( "ii. numerator its 5C3*4C2 for 3 women and therefore 2 men=60, so there are 60 ways \n" ); document.write( "- \n" ); document.write( "iii probability is 60/126 or 10/21. \n" ); document.write( "- \n" ); document.write( "iv. at least 3 women includes 3,4,5. We know 60 ways for 3. For 4 it is 5C4*4C1=20 ways and for 5 women there is only one way. Therefore , there is 81/126 probability or 9/14. \n" ); document.write( "v.Look at 2 women this has 5C2*4C3=40 ways \n" ); document.write( "For 1 woman 4C4*5C1=5 ways. \n" ); document.write( "Can't be 0 women. \n" ); document.write( "1woman-4 men=5 ways \n" ); document.write( "2W 3M-40 ways \n" ); document.write( "3W2M-60 ways \n" ); document.write( "4W1M-20 ways \n" ); document.write( "5W0M-1 way \n" ); document.write( "They add up to 126. They have to. \n" ); document.write( "More men then women occurs 4/1 (5 ways) 3/2 (40 ways) no other ways. so probability is 45/126=15/34\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |