document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192787>Question 1192787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "A farmer has chickens and ducks in his farm. If he sells 2 chickens and 3 ducks a day,there would be 100 chickens left when all the ducks are sold. If he sells 3 chickens and 2 ducks a day, there would be 25 chickens left after all the ducks are sold.<BR>\n" );
document.write( "Find the number of ducks and chickens on the farm. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824687 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Number of days to sell D ducks is (D/3). During that time, 2D/3 chickens will be sold.<BR>\n" );
document.write( "so C-(2D/3)=100, and for the other D/2 days to sell them <BR>\n" );
document.write( "so C-(3D/2)=25<BR>\n" );
document.write( "subtract and (5D/6)=75 and D=90, C=160<BR>\n" );
document.write( "160 chickens and 90 ducks<BR>\n" );
document.write( "in 30 days at 3 a day, the ducks are gone and there are 60 fewer chickens, 100.<BR>\n" );
document.write( "in 45 days at 2 a day, the ducks are gone and 135 fewer chickens, leaving 25.\r<BR>\n" );
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