document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192785>Question 1192785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A soda machine dispenses soda into 16-ounce cups. Tests shows that the actual amount of soda dispensed has a mean of 15.85 oz and a standard deviation of 9.5 oz. A sample of 12 cups is taken. What is the probability that the sample mean is between 14.75 and 22.5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824685 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sigma/sqrt(n)<BR>\n" );
document.write( "z=(14.75-15.85)/9.5/sqrt(12)=-1.10*sqrt(12)/9.5=-0.40<BR>\n" );
document.write( "z=(22.5-15.85)/9.5/sqrt(12)=2.42<BR>\n" );
document.write( "that probability is 0.6477.<BR>\n" );
document.write( "The sd of the sample mean is 9.5/sqrt(12)=2.74<BR>\n" );
document.write( "There is rounding of the z value above. If done on the calculator without rounding, the probability is 0.6481. </SPAN>\n" );
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