document.write( "Question 1192771: A widget manufacturer estimates that her monthly revenue can be modeled by the function R(x)=-0.006x^2+32x-10,000. What is the minimum number of items that must be sold for the revenue to equal $30,000? \n" ); document.write( "
Algebra.Com's Answer #824664 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Method 1:
\n" ); document.write( "Use your favorite graphing tool to plot the two equations
\n" ); document.write( "y = -0.006x^2+32x-10,000
\n" ); document.write( "y = 30,000\r
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\n" ); document.write( "\n" ); document.write( "Here's what it looks like in Desmos which is a free online graphing calculator
\n" ); document.write( "https://www.desmos.com/calculator/tnzwh3datm
\n" ); document.write( "Take note of how the x and y axis scale is set up.\r
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\n" ); document.write( "\n" ); document.write( "After plotting both the parabolic curve and straight line, click on where they intersect or cross.
\n" ); document.write( "Desmos will display the (x,y) coordinates of each intersection point.\r
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\n" ); document.write( "\n" ); document.write( "The two intersection points are:
\n" ); document.write( "(2000, 30000)
\n" ); document.write( "(3333.333, 30000) approximately
\n" ); document.write( "When doing ordered pair notation, do NOT have a comma in the number \"30000\" aka \"thirty thousand\". This is because the comma is used to separate the x and y coordinates.\r
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\n" ); document.write( "\n" ); document.write( "The x coordinate of the left-most point is what we're after.
\n" ); document.write( "This is the smaller x value such that y = 30,000.
\n" ); document.write( "In other words, it's the minimum amount of items to sell to achieve a revenue of $30,000.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 2000 units.\r
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\n" ); document.write( "\n" ); document.write( "Method 2:
\n" ); document.write( "Instead of graphing two equations, we can graph one equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since we want the revenue R(x) to be $30,000, this means:
\n" ); document.write( "R(x) = 30,000
\n" ); document.write( "-0.006x^2+32x-10,000 = 30,000
\n" ); document.write( "-0.006x^2+32x-10,000 - 30,000 = 0
\n" ); document.write( "-0.006x^2+32x-40,000 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The single equation to graph is
\n" ); document.write( "y = -0.006x^2+32x-40,000\r
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\n" ); document.write( "\n" ); document.write( "When graphing this, we're looking for the x intercepts which make y = 0. Therefore, we're looking where the curve either crosses the x axis or touches it to bounce away.\r
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\n" ); document.write( "\n" ); document.write( "Graph:
\n" ); document.write( "https://www.desmos.com/calculator/vuz7masgvd
\n" ); document.write( "As the graph shows, the x coordinates of the x intercepts are the same as the results of method 1. The only difference is now that y = 0 instead of y = 30,000.\r
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\n" ); document.write( "\n" ); document.write( "We'll arrive at the same final answer of 2000 units after selecting the smaller root.\r
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\n" ); document.write( "\n" ); document.write( "Method 3:
\n" ); document.write( "This method won't use any graphs. Instead, I'll use the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( "R(x) = 30,000
\n" ); document.write( "-0.006x^2+32x-10,000 = 30,000
\n" ); document.write( "-0.006x^2+32x-10,000 - 30,000 = 0
\n" ); document.write( "-0.006x^2+32x-40,000 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "That final equation is in the form ax^2+bx+c = 0 where,
\n" ); document.write( "a = -0.006
\n" ); document.write( "b = 32
\n" ); document.write( "c = -40,000\r
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\n" ); document.write( "\n" ); document.write( "Plugging those three items into the quadratic formula yields:
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-32%2B-sqrt%2864%29%29%2F%28-0.012%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-32%2B-+++8%29%2F%28-0.012%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-32%2B8%29%2F%28-0.012%29\" or \"x+=+%28-32-8%29%2F%28-0.012%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24%29%2F%28-0.012%29\" or \"x+=+%28-40%29%2F%28-0.012%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+2000\" or \"x+=+3333.333\" approximately\r
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\n" ); document.write( "\n" ); document.write( "Like before, we pick the smaller x solution to get 2000 units as the final answer.
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