document.write( "Question 113324: Find the circumference of a circle inscribed in an equilateral triangle if the height of the triangle is 14 in. \n" ); document.write( "
Algebra.Com's Answer #82465 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
THIS EQUILATERAL TRIANGLE WITH A HEIGHT OF 14 IN. HAS SIDES OF:
\n" ); document.write( "14/SQRT3=X/2 (THIS IS HALF OF THE TRIANGLE FORMED BY THE HEIGHT, 1 SIDE & HALF THE BASE)
\n" ); document.write( "SQRT3*X=28
\n" ); document.write( "X=28/SQRT3
\n" ); document.write( "X=16.66 IN. FOR THE LENGTH OF THE SIDES.
\n" ); document.write( "NOW DISECT ONE OF THE LOWER ANGLES FORMINGA 30-6-90 DEGREE TRIANGLE WITH ONE HALF THE SIDE(8.083 IN)OPPOSITE THE 60 DEGREE ANGLE.
\n" ); document.write( "THEREFORE THE OTHER SIDE IS:
\n" ); document.write( "X/1=8.083/SQRT3
\n" ); document.write( "X=8.083/1.732
\n" ); document.write( "X=4.667 IN FOR THE RADIUS.
\n" ); document.write( "THUS THE CIRCUMFERANCE OF THE INSCRIBED CIRCLE IS 2*PI*4.667=29.3 INCHES.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );