document.write( "Question 1192743: solve cos2x-2sinx-cos^2 x = -3 on the interval x ∈ [0,2π] \n" ); document.write( "
Algebra.Com's Answer #824646 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"cos%282x%29-2sin%28x%29-cos%5E2+%28x%29+=+-3\" on the interval \"x\" ∈ [\"0\",\"2%CF%80\"]\r
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\n" ); document.write( "\n" ); document.write( "since \"cos%282x%29=cos%5E2%28x%29+-+sin%5E2%28x%29\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"cos%5E2%28x%29+-+sin%5E2%28x%29-2sin%28x%29-cos%5E2+%28x%29+=+-3+\"\r
\n" ); document.write( "\n" ); document.write( " \"-sin%5E2%28x%29-2sin%28x%29=+-3+\"\r
\n" ); document.write( "\n" ); document.write( " \"-3sin%5E2%28x%29=+-3\" \r
\n" ); document.write( "\n" ); document.write( "\"+sin%5E2%28x%29=+-3%2F-3+\"\r
\n" ); document.write( "\n" ); document.write( "\"+sin%5E2%28x%29=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"+sin%28x%29=+sqrt%281%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28x%29=+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=sin%5E-1%281%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=pi%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "periodicity of sin is \"2pi\"\r
\n" ); document.write( "\n" ); document.write( "general solution:\r
\n" ); document.write( "\n" ); document.write( "\"x=pi%2F2%2B2pi%2An\"\r
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\n" ); document.write( "\n" ); document.write( "on the interval \"x\" ∈ [\"0\",\"2%CF%80\"] : \"x=pi%2F2\"\r
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