document.write( "Question 1192719: Sand is being poured at a rate of 0.50 m^3/min onto a conical pile whose radius is always equal to 2/3 of its height. At one point in time, an observer notices that the height of the sand pile is increasing at a rate of 8.0 cm/min. What was the height of the pile at this instant? \n" ); document.write( "
Algebra.Com's Answer #824625 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "r = radius in meters \n" ); document.write( "h = height in meters \n" ); document.write( "t = time in minutes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "dr/dt = change in radius over change in time, ie speed at which the radius changes \n" ); document.write( "dh/dt = change in height over change in time, ie speed at which the height changes \n" ); document.write( "Each speed is measured in meters per minute.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100 cm = 1 m \n" ); document.write( "8.0 cm/min = (8.0 cm/min)*(1 m/100 cm) = 0.08 meters per minute\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sentence \n" ); document.write( "\"height of the sand pile is increasing at a rate of 8.0 cm/min\" \n" ); document.write( "is equivalent to \n" ); document.write( "\"height of the sand pile is increasing at a rate of 0.08 m/min\". \n" ); document.write( "This is the dh/dt value for this snapshot in time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = (2/3)h since the radius is 2/3 the height \n" ); document.write( "That rearranges into \n" ); document.write( "3r = 2h \n" ); document.write( "h = 3r/2 \n" ); document.write( "h = 1.5r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Apply the derivative with respect to t to both sides \n" ); document.write( "h = (3/2)r \n" ); document.write( "dh/dt = (3/2)*dr/dt \n" ); document.write( "dh/dt = (3/2)*dr/dt\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in dh/dt = 0.08 mentioned earlier and solve for dr/dt \n" ); document.write( "dh/dt = (3/2)*dr/dt \n" ); document.write( "dr/dt = (2/3)*dh/dt \n" ); document.write( "dr/dt = (2/3)*0.08 \n" ); document.write( "dr/dt = (2/3)*(8/100) \n" ); document.write( "dr/dt = 16/300 \n" ); document.write( "dr/dt = 4/75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have this so far: \n" ); document.write( "h = 3r/2 = 1.5r \n" ); document.write( "dr/dt = 4/75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Recall the volume of a cone with radius r and height h is \n" ); document.write( "V = (1/3)*pi*r^2*h\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subsitution allows us to say \n" ); document.write( "V = (1/3)*pi*r^2*h \n" ); document.write( "V = (1/3)*pi*r^2*(3r/2) \n" ); document.write( "V = (1/3)*(3/2)*pi*r^3 \n" ); document.write( "V = (1/2)*pi*r^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Apply the derivative with respect to t \n" ); document.write( "V = (1/2)*pi*r^3 \n" ); document.write( "dV/dt = d/dt[ (1/2)*pi*r^3 ] \n" ); document.write( "dV/dt = (1/2)*pi*d/dt[ r^3 ] \n" ); document.write( "dV/dt = (1/2)*pi*(3r^2 * dr/dt) \n" ); document.write( "Don't forget about the chain rule. \n" ); document.write( "The radius r is a function of t. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll plug in the rate of change of the volume dV/dt = 0.50 m^3/min along with the rate of change in the radius dr/dt = 4/75 \n" ); document.write( "Then we isolate r. \n" ); document.write( "dV/dt = (1/2)*pi*(3r^2 * dr/dt) \n" ); document.write( "0.50 = (1/2)*pi*(3r^2 * 4/75) \n" ); document.write( "0.50 = (2/25)*pi*r^2 \n" ); document.write( "(2/25)*pi*r^2 = 0.50 \n" ); document.write( "pi*r^2 = 0.50*(25/2) \n" ); document.write( "pi*r^2 = 6.25 \n" ); document.write( "r^2 = (6.25)/pi \n" ); document.write( "r = sqrt(6.25/pi)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This leads to \n" ); document.write( "h = (3/2)r \n" ); document.write( "h = (3/2)sqrt(6.25/pi) \n" ); document.write( "which is the exact height in meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This approximates to (3/2)sqrt(6.25/pi) = 2.1157109 meters \n" ); document.write( " \n" ); document.write( " |