document.write( "Question 1192719: Sand is being poured at a rate of 0.50 m^3/min onto a conical pile whose radius is always equal to 2/3 of its height. At one point in time, an observer notices that the height of the sand pile is increasing at a rate of 8.0 cm/min. What was the height of the pile at this instant? \n" ); document.write( "
Algebra.Com's Answer #824625 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "r = radius in meters
\n" ); document.write( "h = height in meters
\n" ); document.write( "t = time in minutes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "dr/dt = change in radius over change in time, ie speed at which the radius changes
\n" ); document.write( "dh/dt = change in height over change in time, ie speed at which the height changes
\n" ); document.write( "Each speed is measured in meters per minute.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "100 cm = 1 m
\n" ); document.write( "8.0 cm/min = (8.0 cm/min)*(1 m/100 cm) = 0.08 meters per minute\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The sentence
\n" ); document.write( "\"height of the sand pile is increasing at a rate of 8.0 cm/min\"
\n" ); document.write( "is equivalent to
\n" ); document.write( "\"height of the sand pile is increasing at a rate of 0.08 m/min\".
\n" ); document.write( "This is the dh/dt value for this snapshot in time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "r = (2/3)h since the radius is 2/3 the height
\n" ); document.write( "That rearranges into
\n" ); document.write( "3r = 2h
\n" ); document.write( "h = 3r/2
\n" ); document.write( "h = 1.5r\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Apply the derivative with respect to t to both sides
\n" ); document.write( "h = (3/2)r
\n" ); document.write( "dh/dt = (3/2)*dr/dt
\n" ); document.write( "dh/dt = (3/2)*dr/dt\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug in dh/dt = 0.08 mentioned earlier and solve for dr/dt
\n" ); document.write( "dh/dt = (3/2)*dr/dt
\n" ); document.write( "dr/dt = (2/3)*dh/dt
\n" ); document.write( "dr/dt = (2/3)*0.08
\n" ); document.write( "dr/dt = (2/3)*(8/100)
\n" ); document.write( "dr/dt = 16/300
\n" ); document.write( "dr/dt = 4/75\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We have this so far:
\n" ); document.write( "h = 3r/2 = 1.5r
\n" ); document.write( "dr/dt = 4/75\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Recall the volume of a cone with radius r and height h is
\n" ); document.write( "V = (1/3)*pi*r^2*h\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subsitution allows us to say
\n" ); document.write( "V = (1/3)*pi*r^2*h
\n" ); document.write( "V = (1/3)*pi*r^2*(3r/2)
\n" ); document.write( "V = (1/3)*(3/2)*pi*r^3
\n" ); document.write( "V = (1/2)*pi*r^3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Apply the derivative with respect to t
\n" ); document.write( "V = (1/2)*pi*r^3
\n" ); document.write( "dV/dt = d/dt[ (1/2)*pi*r^3 ]
\n" ); document.write( "dV/dt = (1/2)*pi*d/dt[ r^3 ]
\n" ); document.write( "dV/dt = (1/2)*pi*(3r^2 * dr/dt)
\n" ); document.write( "Don't forget about the chain rule.
\n" ); document.write( "The radius r is a function of t. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We'll plug in the rate of change of the volume dV/dt = 0.50 m^3/min along with the rate of change in the radius dr/dt = 4/75
\n" ); document.write( "Then we isolate r.
\n" ); document.write( "dV/dt = (1/2)*pi*(3r^2 * dr/dt)
\n" ); document.write( "0.50 = (1/2)*pi*(3r^2 * 4/75)
\n" ); document.write( "0.50 = (2/25)*pi*r^2
\n" ); document.write( "(2/25)*pi*r^2 = 0.50
\n" ); document.write( "pi*r^2 = 0.50*(25/2)
\n" ); document.write( "pi*r^2 = 6.25
\n" ); document.write( "r^2 = (6.25)/pi
\n" ); document.write( "r = sqrt(6.25/pi)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This leads to
\n" ); document.write( "h = (3/2)r
\n" ); document.write( "h = (3/2)sqrt(6.25/pi)
\n" ); document.write( "which is the exact height in meters.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This approximates to (3/2)sqrt(6.25/pi) = 2.1157109 meters
\n" ); document.write( "
\n" ); document.write( "
\n" );