document.write( "Question 1192696: This is more of a calculus question. We are asked to determine epsilon for which the given limit is true.\r
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\n" ); document.write( "\n" ); document.write( "lim = √x^2+4 = 2, where delta (𝛿) = 1
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Algebra.Com's Answer #824593 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The definition of a limit is lim(x-->a) \"+f%28x%29+\" = L if:\r
\n" ); document.write( "\n" ); document.write( " |f(x)-L| < \"epsilon\" for 0 < |x-a| < \"+delta+\"\r
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\n" ); document.write( "\n" ); document.write( "So here, \"delta\" = 1, centered at x=0, so we need to evaluate f(-1) and f(1):
\n" ); document.write( " f(-1) = \"sqrt%28%28-1%29%5E2+%2B+4%29+=+sqrt%285%29+\"
\n" ); document.write( " f(1) = \"sqrt%28%281%29%5E2+%2B+4%29+=+sqrt%285%29+\"\r
\n" ); document.write( "\n" ); document.write( "So the exact value of \"epsilon+\" is \"+f%28x%29-L+\" = \"+highlight%28+sqrt%285%29+-+2+%29+\" or approx. 0.2361\r
\n" ); document.write( "\n" ); document.write( "Here, the function is symmetrical about the limit point x=0. If the function was not symmetrical, you'd evaluate f(x) on both sides of the limit point, and you'd take the larger value of \"epsilon\". \r
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