document.write( "Question 1192688: Skeletal remains had lost 85% of the C-14 they originally contained. Determine the approximate age (in years) of the bones. (Assume the half life of carbon-14 is 5730 years. Round your answer to the nearest whole number.)
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Algebra.Com's Answer #824589 by greenestamps(13216)\"\" \"About 
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\n" ); document.write( "The fraction of the original amount remaining is (1/2)^n, where n is the number of half lives. Since 85% has been lost, 15% remains. So

\n" ); document.write( "\"%281%2F2%29%5En=0.15\"
\n" ); document.write( "\"n%2Alog%281%2F2%29=log%280.15%29\"
\n" ); document.write( "\"n=log%280.15%29%2Flog%281%2F2%29\"
\n" ); document.write( "\"n=2.737\" to 3 decimal places

\n" ); document.write( "The age of the remains is 2.737 half lives:

\n" ); document.write( "\"2.737%285730%29=15683\" to the nearest year.

\n" ); document.write( "Note rounding the age to the nearest whole number is not really reasonable, because radioactive decay is a statistical process which is only APPROXIMATELY exponential.

\n" ); document.write( "ANSWER (according to the instructions): 15683 years

\n" ); document.write( "A more correct answer: ABOUT 15700 years

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