document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192669>Question 1192669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Karina needs 20 liters of a 51% alcohol solution but she has 10% and 90% solutions available. How many liters of the 10% and how many liters of the 90% solutions should she mix to make the 51% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824564 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x liters of 10%=0.10x pure alcohol <BR>\n" );
document.write( "20-x liters of 90%=.9(20-x)=18-.9x pure alcohol.<BR>\n" );
document.write( "they add to 20*0.51 or 10.2 l pure alcohol.<BR>\n" );
document.write( "so -0.8x+18=10.2<BR>\n" );
document.write( "-0.8x=-7.8<BR>\n" );
document.write( "x=9.75 l of 10% or 0.975 l. pure<BR>\n" );
document.write( "20-x=10.25 l of 90% or 9.225  l. pure<BR>\n" );
document.write( "They are very similar volumes and the midpoint between the percentages is 50%, so they should be and slightly more of the more concentrated since 51% is more than 50%. </SPAN>\n" );
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