document.write( "Question 1192669: Karina needs 20 liters of a 51% alcohol solution but she has 10% and 90% solutions available. How many liters of the 10% and how many liters of the 90% solutions should she mix to make the 51% solution? \n" ); document.write( "
Algebra.Com's Answer #824563 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Lesson Mixing two concentrations for known amount of mixture, https://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "v of the 90%
\n" ); document.write( "20-v of the 10%\r
\n" ); document.write( "\n" ); document.write( "\"90v%2B10%2820-v%29=51%2A20\"\r
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\n" ); document.write( "\n" ); document.write( "\"90v%2B10%2A20-10v=51%2A20\"\r
\n" ); document.write( "\n" ); document.write( "\"90v-10v%2B10%2A20=51%2A20\"\r
\n" ); document.write( "\n" ); document.write( "\"%2890-10%29v=51%2A20-10%2A20\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28v=20%2851-10%29%2F%2890-10%29%29\"\r
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