document.write( "Question 1192599: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
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\n" ); document.write( "we have a ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ,and the vertex angle 80 ,you will find the value of 'x' , which is a base angle. Now, once you obtain the BASE ANGLE , you need to \"BISECT\" these base angles, because this will give you the measure of angle ABC and ADC ,
\n" ); document.write( "Then you need to take the \"small\" triangle inside the bigger triangle (ABD),you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1 \n" ); document.write( "
Algebra.Com's Answer #824478 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I just drew the figure and found the angles.That's here:\r\n" );
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document.write( "http://www.algebra.com/tutors/students/your-answer.mpl?question=1192572\r\n" );
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document.write( "Edwin
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