document.write( "Question 1192552: In a figure, curve A whose equation is y=(x+a)^2, passes through the point (4,0).
\n" ); document.write( "Curve B whose equation is y=(x+a)^2+b, passes through the point (4,-9).\r
\n" ); document.write( "\n" ); document.write( "a)Calculate the values of a and b\r
\n" ); document.write( "\n" ); document.write( "b)if the curve B intersects the x-axis at point (p,0) and (q,0), calculate the values of p and q\r
\n" ); document.write( "\n" ); document.write( "c)if curve B intersects the y-axis at the point (0,r), calculate the value of r.
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Algebra.Com's Answer #824418 by Boreal(15235)\"\" \"About 
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y=(x+a)^2
\n" ); document.write( "0=(4+a)^2; a=-4
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\n" ); document.write( "y=(x-4)^2+b the vertex is (-a, b) or (4, -9)
\n" ); document.write( "b=-9
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\n" ); document.write( "0=(x-4)^2-9=x^2-8x+7=(x-1)(x-7)
\n" ); document.write( "p and q are 1 and 7 or 7 and 1
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\n" ); document.write( "r=(0-4)^2-9=7
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