document.write( "Question 16961: can you please help with this question...\r
\n" ); document.write( "\n" ); document.write( "Joseph is 4 years older than twice his sisters age. In 4 years time he will be 11 years older than here. How old is Joseph now
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Algebra.Com's Answer #8244 by venugopalramana(3286)\"\" \"About 
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Joseph is 4 years older than twice his sisters age. In 4 years time he will be 11 years older than her. How old is Joseph now
\n" ); document.write( "let joseph's sister's age now be x yrs.
\n" ); document.write( "twice her age =2x
\n" ); document.write( "4 years older than her would be = 2x+4
\n" ); document.write( "this is joseph's age now as per given data.
\n" ); document.write( "so joseph's age now =2x+4
\n" ); document.write( "after 4 years joseph's sister's age = x+4
\n" ); document.write( "11years older to this would be = x+4+11=x+15.......(1)
\n" ); document.write( "but after 4 years joseph's age = 2x+4+4=2x+8.......(2)
\n" ); document.write( "hence (1)=(2) OR x+15=2x+8
\n" ); document.write( "2x+8=x+15
\n" ); document.write( "2x-x=15-8=7
\n" ); document.write( "x=7....hence joseph's sister's age now =x=7 yrs
\n" ); document.write( "and so joseph's age now =2x+4=2*7+4=14+4=18 yrs.\r
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