document.write( "Question 16961: can you please help with this question...\r
\n" );
document.write( "\n" );
document.write( "Joseph is 4 years older than twice his sisters age. In 4 years time he will be 11 years older than here. How old is Joseph now \n" );
document.write( "
Algebra.Com's Answer #8244 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Joseph is 4 years older than twice his sisters age. In 4 years time he will be 11 years older than her. How old is Joseph now \n" ); document.write( "let joseph's sister's age now be x yrs. \n" ); document.write( "twice her age =2x \n" ); document.write( "4 years older than her would be = 2x+4 \n" ); document.write( "this is joseph's age now as per given data. \n" ); document.write( "so joseph's age now =2x+4 \n" ); document.write( "after 4 years joseph's sister's age = x+4 \n" ); document.write( "11years older to this would be = x+4+11=x+15.......(1) \n" ); document.write( "but after 4 years joseph's age = 2x+4+4=2x+8.......(2) \n" ); document.write( "hence (1)=(2) OR x+15=2x+8 \n" ); document.write( "2x+8=x+15 \n" ); document.write( "2x-x=15-8=7 \n" ); document.write( "x=7....hence joseph's sister's age now =x=7 yrs \n" ); document.write( "and so joseph's age now =2x+4=2*7+4=14+4=18 yrs.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |