document.write( "Question 1192494: find where the tangent to the curve y=x^3 at the point where x=2, meets the curve again \n" ); document.write( "
Algebra.Com's Answer #824378 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "f(x) = x^3

\n" ); document.write( "f(2) = 8

\n" ); document.write( "f'(x) = 3x^2

\n" ); document.write( "f'(2) = 12

\n" ); document.write( "The tangent has slope 12 and passes through the point (2,8); its equation is y=12x-16.

\n" ); document.write( "We are to find the other value of x where the graphs of x^3 and 12x-16 intersect.

\n" ); document.write( "\"x%5E3+=+12x-16\"
\n" ); document.write( "\"x%5E3-12x%2B16=0\"

\n" ); document.write( "We could use standard methods to try to find how that cubic expression factors. However, we know something about that expression that makes it easy to factor.

\n" ); document.write( "We know that the graph of y=12x-16 is tangent to the graph of y=x^3 at x=2. That means that cubic equation has a double root at x=2. Removing that double root shows us that

\n" ); document.write( "\"x%5E3-12x%2B16=%28x%2B4%29%28x-2%29%5E2\"

\n" ); document.write( "so the other point where the tangent intersects the graph of y=x^3 is when x=-4; that point of intersection is (-4,-64).

\n" ); document.write( "A graph....

\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-100%2C60%2Cx%5E3%2C12x-16%29\"

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