document.write( "Question 1192494: find where the tangent to the curve y=x^3 at the point where x=2, meets the curve again \n" ); document.write( "
Algebra.Com's Answer #824378 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "f(x) = x^3 \n" ); document.write( "f(2) = 8 \n" ); document.write( "f'(x) = 3x^2 \n" ); document.write( "f'(2) = 12 \n" ); document.write( "The tangent has slope 12 and passes through the point (2,8); its equation is y=12x-16. \n" ); document.write( "We are to find the other value of x where the graphs of x^3 and 12x-16 intersect. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We could use standard methods to try to find how that cubic expression factors. However, we know something about that expression that makes it easy to factor. \n" ); document.write( "We know that the graph of y=12x-16 is tangent to the graph of y=x^3 at x=2. That means that cubic equation has a double root at x=2. Removing that double root shows us that \n" ); document.write( " \n" ); document.write( "so the other point where the tangent intersects the graph of y=x^3 is when x=-4; that point of intersection is (-4,-64). \n" ); document.write( "A graph.... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |