document.write( "Question 113289This question is from textbook Beginning and Intermediate Algebra
\n" ); document.write( ": the height in feet of a projectile after t seconds is given by h(t)=-16t^2 +96t
\n" ); document.write( "determine the values for which the projectile is at the ground.\r
\n" ); document.write( "\n" ); document.write( "(the -16 has an exponent of 2 I couldn't get it to show up right also I need to set this problem up as an equation the chapter we are working on has to do with factoring.)
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Algebra.Com's Answer #82437 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The height of an object, as a function of time, t, propelled upwards from an initial height \"h%5B0%5D\" with an initial velocity \"v%5B0%5D\" is given by:
\n" ); document.write( "\"h%28t%29+=-16t%5E2%2Bv%5B0%5Dt%2Bh%5B0%5D\"
\n" ); document.write( "In your problem:
\n" ); document.write( "\"v%5B0%5D+=+96\"ft.
\n" ); document.write( "\"h%5B0%5D+=+0\"ft.... or on the ground.
\n" ); document.write( "You want to find the values of t for which h = 0, so substitute h=0 and solve for t.
\n" ); document.write( "\"0+=+-16t%5E2%2B96t\" Factor a t.
\n" ); document.write( "\"0+=+t%28-16t%2B96%29\" Apply the zero product principle.
\n" ); document.write( "\"t+=+0\" and
\n" ); document.write( "\"16t+=+96\" Divide both sides by 16.
\n" ); document.write( "\"t+=+6\"
\n" ); document.write( "So the height of the projectile is 0 (on the ground) at times, t = 0 secs and t = 6 secs.
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