document.write( "Question 113156This question is from textbook
\n" ); document.write( ": Having a real hard time with this...please help!\r
\n" ); document.write( "\n" ); document.write( "Solve system of equation word problem but either addition method or substitution method.\r
\n" ); document.write( "\n" ); document.write( "George has two investments that yield a total of $185.60 in annual interest. The amount invested at 8% is $320 less than twice the amount invested at 6%. How much is invested at each rate?\r
\n" ); document.write( "\n" ); document.write( "Amount invested at 8% _________
\n" ); document.write( "Amount invested at 6% _________ \n" ); document.write( "
Algebra.Com's Answer #82419 by SHUgrad05(58)\"\" \"About 
You can put this solution on YOUR website!
To set up this word problem,it's good to start writing out what we know:
\n" ); document.write( "We know George has two investments (let's call them x & y), one at 6% and the other at 8%.
\n" ); document.write( "The two investments yield a total of $185.60 in annual interest.
\n" ); document.write( "So, 0.06x+0.08y=185.60
\n" ); document.write( "Next:
\n" ); document.write( "We know the amount invested at 8% is $320 less than twice the amount invested at 6% which means: y=2x-320.
\n" ); document.write( "So that leaves us with: 0.06x+0.08y=185.60 and y=2x-320
\n" ); document.write( "Use the substitution method to continue solving. \r
\n" ); document.write( "\n" ); document.write( "0.06x+0.08(2x-320)=185.60
\n" ); document.write( "0.06x+0.16x-25.60=185.60
\n" ); document.write( "0.22x=211.20
\n" ); document.write( "x=$960.00\r
\n" ); document.write( "\n" ); document.write( "0.06(960)+0.08y=185.60
\n" ); document.write( "57.60+0.08y=185.60
\n" ); document.write( "0.08y=128.00
\n" ); document.write( "y=$1600\r
\n" ); document.write( "\n" ); document.write( "Amt invested at 6%=$960.00
\n" ); document.write( "Amt invested at 8%=$1600.00
\n" ); document.write( " \n" ); document.write( "
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