document.write( "Question 1192183: The daily demand for copies of a movie magazine at a variety at a variety store has the probability distribution as follows.
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document.write( "Number of Copies X
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document.write( "Probability P(X)\r
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document.write( "0
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document.write( "0.06\r
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document.write( "1
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document.write( "0.14\r
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document.write( "2
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document.write( "0.16\r
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document.write( "3
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document.write( "0.14\r
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document.write( "4
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document.write( "0.12\r
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document.write( "5
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document.write( "0.10\r
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document.write( "6
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document.write( "0.08\r
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document.write( "7
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document.write( "0.07\r
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document.write( "8
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document.write( "0.06\r
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document.write( "9
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document.write( "0.04\r
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document.write( "10
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document.write( "0.03\r
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document.write( "What is the probability that three or more copies will be demanded in a particular day?
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document.write( "Solution:\r
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document.write( "What is the probability that the demand will be at least two but not more than six?
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document.write( "Solution: \n" );
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Algebra.Com's Answer #824180 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! greater than or =3 has probability of 0.64. It is 1- probability of (0,1,and2) \n" ); document.write( "- \n" ); document.write( "at least 2 but not more than six. Add the probabilities for 2,3,4,5,6=0.60 \n" ); document.write( " |