document.write( "Question 1192241: A researcher wishes to estimate the proportion of college students who own a car. He wants to be 95% confident and be accurate within 8% of the true proportion. find the minimum sample necessary. \n" ); document.write( "
Algebra.Com's Answer #824168 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "In your stats class, you should have come across the margin of error for a confidence interval involving proportions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That particular margin of error formula is: \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's solve for n \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "sqrt(phat*(1-phat)/n) = E/z \n" ); document.write( "phat*(1-phat)/n = (E/z)^2 \n" ); document.write( "n/( phat*(1-phat) ) = (z/E)^2 \n" ); document.write( "n = phat*(1-phat)(z/E)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 95% confidence, the z critical value is about z = 1.96 which is determined through a Z table or a calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Unfortunately we don't know what phat is, so we'll have to go with the conservative estimate of phat = 0.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The desired error we want is E = 0.08, since we want to be within 8% of the true proportion p. \n" ); document.write( "The phrasing \"within\" is the same as saying \"at most\". So we want the error to be at most 0.08, ie we want \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in those items mentioned \n" ); document.write( "n = phat*(1-phat)(z/E)^2 \n" ); document.write( "n = 0.5*(1-0.5)(1.96/0.08)^2 \n" ); document.write( "n = 150.0625\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Despite this value of n being very close to 150, we always round up when it comes to minimum sample size problems like this. \n" ); document.write( "Why up? Because it ensures we clear the hurdle. \n" ); document.write( "The larger n gets, the smaller E gets. \n" ); document.write( "Intuitively this fits with the idea that a larger sample is more representative; hence it would more accurately capture the parameter we're after (leading to reduced error).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say we go with n = 150 \n" ); document.write( "Calculating the margin of error gets us \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.96*sqrt(0.5*(1-0.5)/150) \n" ); document.write( "E = 0.08001666493091 \n" ); document.write( "This error is a bit too high, as it is larger than 0.08 \n" ); document.write( "Though you could argue that rounding it to two decimal places gets us E = 0.08 just fine.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Standard practice is to round up to ensure E is under 0.08 \n" ); document.write( "So if we go for n = 151 then we have \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.96*sqrt(0.5*(1-0.5)/151) \n" ); document.write( "E = 0.07975126895958 \n" ); document.write( "We've cleared the hurdle and E is now smaller than 0.08\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Min sample size = 151 \n" ); document.write( " \n" ); document.write( " |