document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192254>Question 1192254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	A construction company has bid on two contracts. The probability of winning contract A is 0.3. If the company wins contract A, then the probability of winning contract B is 0.4. If the company loses, contract A, then the probability of winning contract B decreases to 0.2. Find the probability of the following events:(full details)<BR>\n" );
document.write( "A.	Winning both contracts.<BR>\n" );
document.write( "B.	Winning exactly one contract.<BR>\n" );
document.write( "C.	Winning at least one contract.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824160 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> winning both is 0.3*0.4=0.12<BR>\n" );
document.write( "winning neither 0.7*0.8, the complement of winning=0.56<BR>\n" );
document.write( "winning at least 1 is the complement of the second one, or 0.56, and that is 1-0.56=0.44<BR>\n" );
document.write( "winning A alone is 0.3*0.6=0.18<BR>\n" );
document.write( "winning B alone is 0.7*0.2=0.14<BR>\n" );
document.write( "Ignoring the at least 1, the other four add to 1.0, which they must.<BR>\n" );
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