document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192234>Question 1192234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the speed of a boat in still water is 30 mph. It takes the same time for the boat to travel 5 miles upstream as it does to travel 10 miles downstream. Find the speed of the currrent<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824149 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor showed a solution using what is probably the standard algebraic method.<br><BR>\n" );
document.write( "Here is an alternative that I personally think is a bit easier.<br><BR>\n" );
document.write( "The times are the same, and the downstream distance is twice the upstream distance.  That means the downstream speed is twice the upstream speed.<br><BR>\n" );
document.write( "So if c is the speed of the current, then<br><BR>\n" );
document.write( "30+c=2(30-c)<BR>\n" );
document.write( "30+c=60-2c<BR>\n" );
document.write( "3c=30<BR>\n" );
document.write( "c=10<br><BR>\n" );
document.write( "ANSWER: The speed of the current is 10mph<br>\r<BR>\n" );
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