document.write( "Question 1192247: The salary of 500 employees of a production home follows normal distribution with mean 5700 taka as well as SD 500.Find probability of
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document.write( "(a)salary more than 5800 taka
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document.write( "(b)salary between 5200-6000 taka \n" );
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Algebra.Com's Answer #824145 by Theo(13342)![]() ![]() You can put this solution on YOUR website! mean = 5700 \n" ); document.write( "standard deviation = 500 \n" ); document.write( "z-score = (x - m) / s \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation. \n" ); document.write( "when x = 5800, z = (5800 - 5700) / 500 = .2 \n" ); document.write( "i used the z-score table at https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf \n" ); document.write( "that table gives you the area to the left of the z-score. \n" ); document.write( "area to the left of a z-score of .2 = .57926 \n" ); document.write( "area to the right of that z-score = 1 - .57926 = .42074 \n" ); document.write( "that's the probability of getting a score greater than 5800. \n" ); document.write( "to get the probability between two z-scores, you want to get the low z-score and the high z-score and take the area to the left of each and then subtract the smaller area from the larger area. \n" ); document.write( "when x = 5200, z = (5200 - 5700) / 500 = -1. \n" ); document.write( "area to the left of that z-score = .15866 \n" ); document.write( "when x = 6000, z = (6000 - 5700) / 500 = .6 \n" ); document.write( "area to the left of that z-score = .72575 \n" ); document.write( "area in between = .72575 - .15866 = .56709 \n" ); document.write( "that's the probability of getting a score between 5200 and 6000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |