document.write( "Question 1192213: A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10-
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document.write( "coins, and 14 less ₱1-coins as ₱5-coins. How many of each kind were there? \n" );
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Algebra.Com's Answer #824115 by ikleyn(52782)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10- \n" ); document.write( "coins, and 14 less ₱1-coins as ₱5-coins. How many of each kind were there? \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let x be the number of P10-coins.\r\n" ); document.write( "\r\n" ); document.write( "Then the number of P5-coins is 2x and the number of P1-coins is (2x-14).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now write the total money equation\r\n" ); document.write( "\r\n" ); document.write( " 10x + 5*(2x) + 1*(2x-14) = 1570.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x\r\n" ); document.write( "\r\n" ); document.write( " 10x + 10x + 2x - 14 = 1570\r\n" ); document.write( "\r\n" ); document.write( " 22x = 1570 + 14\r\n" ); document.write( "\r\n" ); document.write( " 22x = 1584\r\n" ); document.write( "\r\n" ); document.write( " x = 1584/22 = 72.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. There are 72 P10-coins; 722*2 = 144 P5-coins and 144 - 14 = 130 P1-coins.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "CHECK. 10*72 + 5*144 + 130 = 1570, total money. ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |