document.write( "Question 113235: can you find by mod (100) the last two number of\r
\n" ); document.write( "\n" ); document.write( "\"2%5E100\"
\n" ); document.write( "and
\n" ); document.write( "\"2%5E2006\"
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Algebra.Com's Answer #82408 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
find by mod (100) the last two number of\r
\n" ); document.write( "\n" ); document.write( "2^100\r
\n" ); document.write( "\n" ); document.write( "= 2^(10^2)\r
\n" ); document.write( "\n" ); document.write( "= [2^10]^2\r
\n" ); document.write( "\n" ); document.write( "= [1024]^2\r
\n" ); document.write( "\n" ); document.write( "= 24^2 (mod 100)\r
\n" ); document.write( "\n" ); document.write( "= 576 (mod 100)\r
\n" ); document.write( "\n" ); document.write( "= 76 (mod 100)\r
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\n" ); document.write( "\n" ); document.write( "and
\n" ); document.write( "2^2006\r
\n" ); document.write( "\n" ); document.write( "2^100 = 76 (mod 100)
\n" ); document.write( "2^200 = 5776 = 76 (mod 100)
\n" ); document.write( "2^400 = 5776 (mod100) = 76 (mod 100)
\n" ); document.write( "2^800 = 2^1600 = 76 (mod 100)
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\n" ); document.write( "2^2006 = 2^1600*2^400*2^6 = 76*76*64 (mod 100)
\n" ); document.write( "= 76*64 mod 100
\n" ); document.write( "= 4864 mod 100
\n" ); document.write( "= 64 mod 100
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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