document.write( "Question 1192124: A certain company manufactures precision thermometers that are supposed to give readings of 0.00° C at the freezing point of water. Tests on a large sample of these thermometers reveal that some give readings above 0.00° C and some give readings below 0.00° C. Suppose thermometer readings are approximately normally distributed with mean thermometer 0.00° C with a standard deviation of 1.00°. What is the thermometer reading that separates the top 4% of readings from the rest? (Round your answer to two decimal places; add trailing zeros as needed.) \n" ); document.write( "
Algebra.Com's Answer #824039 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Use a calculator like this \n" ); document.write( "https://davidmlane.com/normal.html \n" ); document.write( "Click \"Value from an area\" \n" ); document.write( "Input 0.04 as the area \n" ); document.write( "Input 0 as the mean \n" ); document.write( "Input 1 as the standard deviation \n" ); document.write( "Click the \"above\" option and hit \"recalculate\" to have 1.751 result. \n" ); document.write( "This means that 4% of the area is to the right of 1.751\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This rounds to 1.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alternative Path\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want to use a table instead of a calculator, then you can use something like this \n" ); document.write( "https://www.ztable.net \n" ); document.write( "Locate 0.04 in the table or try to get as close as you can to it. \n" ); document.write( "The value 0.04006 is as close as we can get \n" ); document.write( "Trace to the left until you get to -1.7 at the very left \n" ); document.write( "Trace up the column until you arrive at 0.05 at the very top \n" ); document.write( "Refer to the diagram below. \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The headers -1.7 and 0.05 combine to -(1.7+0.05) = -1.75 \n" ); document.write( "This shows P(Z < -1.75) = 0.04006 approximately \n" ); document.write( "Due to mirror symmetry, we can say P(Z > 1.75) = 0.04006 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, we can see that 1.75 is the top 4% cut off point, aka its the value of the 96th percentile since about 96% of the distribution is below z = 1.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1.75 \n" ); document.write( " \n" ); document.write( " |