document.write( "Question 1192097: Two sides of a parallelogram measure 68cm and 83cm. Its smaller diagonal has a measure of 42cm. Find the largest interior angle of the parallelogram​. \n" ); document.write( "
Algebra.Com's Answer #823999 by ikleyn(52803)\"\" \"About 
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document.write( "Use the cosine law.\r\n" );
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document.write( "Find smaller interior angle \"a\" \r\n" );
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document.write( "    42^2 = 68^2 + 83^2 - 2*68*83*cos(a)\r\n" );
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document.write( "    cos(a) = \"%2868%5E2%2B83%5E2-42%5E2%29%2F%282%2A68%2A83%29\" = 0.863660524.\r\n" );
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document.write( "        a  = arccos(0.863660524) = 30.2698952  degrees.\r\n" );
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document.write( "Hence, the largest interior angle of the parallelogram is  180 - 30.2698952 = 149.73 degrees  (rounded).    ANSWER\r\n" );
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