document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191970>Question 1191970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an isosceles triangle ABC, side AB is twice as long as AC. The perimeter of the triangle is 200cm. Find the length of AC. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823995 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "One side is twice the length of the other, so we can call those two side lengths x and 2x.<br><BR>\n" );
document.write( "And the triangle is isosceles, so the length of the third side is either x or 2x.<br><BR>\n" );
document.write( "But the lengths x, x, and 2x do not form a triangle.<br><BR>\n" );
document.write( "So the length of the third side is 2x.<br><BR>\n" );
document.write( "The perimeter is 200cm:<br><BR>\n" );
document.write( "x+2x+2x = 200<BR>\n" );
document.write( "5x = 200<BR>\n" );
document.write( "x = 40<BR>\n" );
document.write( "2x = 80<br><BR>\n" );
document.write( "The triangle side lengths are 40, 80, and 80.<br><BR>\n" );
document.write( "The question asks for the length of AC, which is the shortest side.<br><BR>\n" );
document.write( "ANSWER: AC = 40cm<br><BR>\n" );
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