document.write( "Question 1192061: The fill amount in 2-liter soft drink bottles is normally distributed, with a mean of 2.0 liters and a
\n" );
document.write( "standard deviation of 0.05 liter. If bottles contain less than 95% of the listed net content (1.90 liters, in
\n" );
document.write( "this case), the manufacturer may be subject to penalty by the state office of consumer affairs. Bottles
\n" );
document.write( "that have a net content above 2.10 liters may cause excess spillage upon opening. What proportion of
\n" );
document.write( "the bottles will contain
\n" );
document.write( "a. between 1.90 and 2.0 liters?
\n" );
document.write( "b. between 1.90 and 2.10 liters?
\n" );
document.write( "c. below 1.90 liters or above 2.10 liters?
\n" );
document.write( "d. At least how much soft drink is contained in 99% of the bottles?
\n" );
document.write( "e. 99% of the bottles contain an amount that is between which two values (symmetrically distributed) around
\n" );
document.write( "the mean?\r
\n" );
document.write( "\n" );
document.write( "I've solved the first four question, only need help with the last one.
\n" );
document.write( "Thanks. \n" );
document.write( "
Algebra.Com's Answer #823949 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 99% half-interval around the mean is z(0.995)*sigma/sqrt(n) \n" ); document.write( "=2.576*0.05 \n" ); document.write( "=0.1288 or 0.13 l, \n" ); document.write( "(1.87, 2.13) liters will be found in 99% of the bottles. \n" ); document.write( " |