document.write( "Question 1192056: You and a friend go to Tacos Galore for lunch. You order three soft tacos and three burritos and your total bill is $11.25. Your friend's bill is $10.00 for four soft tacos and two burritos. How much do soft tacos cost? How much do burritos cost? \n" ); document.write( "
Algebra.Com's Answer #823945 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "First an informal solution using logical reasoning and simple arithmetic. You can get some good mental exercise solving problems like that.

\n" ); document.write( "3 tacos and 3 burritos cost $11.25; 4 tacos and 2 burritos cost $10. The difference is 1 more taco and 1 less burrito, for $1.25 less.

\n" ); document.write( "So adjust the order repeatedly the same way, adding one taco and taking away one more burrito, and decreasing the cost by $1.25 each time.
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document.write( "3 tacos, 3 burritos, $11.25\r\n" );
document.write( "4 tacos, 2 burritos, $10.00\r\n" );
document.write( "5 tacos, 1 burrito,   $8.75\r\n" );
document.write( "6 tacos, 0 burritos,  %7.50

\n" ); document.write( "The cost of each taco is $7.50/6 = $1.25.

\n" ); document.write( "3 of each cost $11.25, so 1 of each cost $3.75; the taco costs $1.25, so the burrito costs $2.50.

\n" ); document.write( "ANSWERS: taco $1.25, burrito $2.50

\n" ); document.write( "Then here is one of many ways to work the problem with formal algebra....

\n" ); document.write( "3t+3b=11.25
\n" ); document.write( "4t+2b=10

\n" ); document.write( "With the two equations in that form, a solution by elimination is probably easiest. Multiply each equation by some constant so that the coefficients of b are opposites, so that b disappears when the two equations are added.
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document.write( "-6t-6b=-22.50\r\n" );
document.write( "12t+6b= 30.00\r\n" );
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document.write( " 6t   =  7.50

\n" ); document.write( "t = 7.50/6 = 1.25

\n" ); document.write( "Plug that into either of the original equations to find b:

\n" ); document.write( "4(1.25)+2b=10
\n" ); document.write( "5+2b=10
\n" ); document.write( "2b=5
\n" ); document.write( "b=2.50

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