document.write( "Question 1192058: If n=5 and p=0.2 of binomial distribution.find P(X greater than 3)=? \n" ); document.write( "
Algebra.Com's Answer #823941 by Theo(13342)\"\" \"About 
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n = 5 and p = .2
\n" ); document.write( "q = 1 - p = .8
\n" ); document.write( "x = 0 to 5
\n" ); document.write( "formula is:
\n" ); document.write( "p(x) = p^x * q^(n-x) * c(n,x)
\n" ); document.write( "when p = .2 and q = .8 and n = 5, formula becomes:
\n" ); document.write( "p(x) = .2^x * .8^(n-x) * c(5,x)
\n" ); document.write( "p(x>3) would be equal to p(4) + p(5)
\n" ); document.write( "p(4) = .2^4 * .8^1 * c(5,4) = .0064
\n" ); document.write( "p(5) = .2^5 * .8^0 * c(5,5) = .00032
\n" ); document.write( "add them up and you get:
\n" ); document.write( "p(x>3) = .00672
\n" ); document.write( "that's your answer.\r
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