document.write( "Question 1192021: The GMS Company packages their wood mulch in 50-kilogram bags. The
\n" ); document.write( "packaging department reports that the standard deviation of this process is 1.36
\n" ); document.write( "kilograms per bag. At the end of each day, the production manager, weighs 160
\n" ); document.write( "bags and computes the mean weight of the sample of 49.2 kilograms. Can it be
\n" ); document.write( "concluded that the mean weight of the sample is less than 50 kilograms? Use the
\n" ); document.write( "0.01 significant level.\r
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Algebra.Com's Answer #823909 by Theo(13342)\"\" \"About 
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standard deviation = 1.36
\n" ); document.write( "sample size = 160
\n" ); document.write( "sample mean = 49.2
\n" ); document.write( "critical z-score at one tail .01 significance level = -2.33.
\n" ); document.write( "critical z-score at two tail .01 significance level = -2.58
\n" ); document.write( "standard error = 1.36 / sqrt(160) = .1075
\n" ); document.write( "z-score = (49.2 - 50) / .1075 = -7.44.
\n" ); document.write( "this is way greater than the critical z-score.
\n" ); document.write( "the results are significant.
\n" ); document.write( "you can conclude that the mean weight of the sample is definitely less than 50 kilograms.
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