document.write( "Question 1191984: (a) The first term of an arithmetic progression is 7 and the common difference is 2. Find the 15th term and the sum of the first 15th term.
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document.write( "(b) how many terms of the sequence -9,-6,-3 must be taken that the sum maybe 66.
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document.write( "(c) find the sum of the first 25 even integers. \n" );
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Algebra.Com's Answer #823879 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! sum=(n/2)(2a+(n-1)d) \n" ); document.write( "nth term =a1+(n-1)d \n" ); document.write( "a. n15=7+(15-1)2=35 \n" ); document.write( "Sum is (15/2)(14+14*2)=315 \n" ); document.write( "7+9+11+13+15+17+19+21+23+25+27+29+31+33+35=315 \n" ); document.write( "- \n" ); document.write( "a1=-9, d=3, sum=66 \n" ); document.write( "66=(n/2)(-18+(n-1)3)=(n/2)(-18+3n-3)=(n/2)(3n-21) \n" ); document.write( "multiply by 2 to clear fractions \n" ); document.write( "132=3n^2-21n \n" ); document.write( "n^2-7n-44=0 dividing by 3 and rearranging. \n" ); document.write( "(n-11)(n+4)=0 \n" ); document.write( "n=11 terms only positive root. \n" ); document.write( "-9,-6,-3,0,3,6,9,12,15,18,21 \n" ); document.write( "- \n" ); document.write( "This is n(n+1) where n=25 \n" ); document.write( "The answer is 650. \n" ); document.write( " \n" ); document.write( " |