document.write( "Question 1191999: Form a fifth-degree polynomial function with real coefficients such that 5i, 1-3i, and -3 are zeros and f(0)=1500 \n" ); document.write( "
Algebra.Com's Answer #823874 by Boreal(15235)\"\" \"About 
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complex roots are conjugate
\n" ); document.write( "roots are +/-5i
\n" ); document.write( "1-3i, 1+3i
\n" ); document.write( "-3
\n" ); document.write( "Two factors are (x^2+25)(x+3)
\n" ); document.write( "The other two are (x+1+3i) (x-1-3i)
\n" ); document.write( "multiply those to get x^2-2x+10, which has roots (1/2)(2+/-sqrt(-36)) or (1/2) (2+/-6i)
\n" ); document.write( "=x^2-2x+10
\n" ); document.write( "a(x^2+25)(x+3)(x^2-2x+10) is the polynomial
\n" ); document.write( "when x=0 the value is 25*3*10=750, so a must be 2.
\n" ); document.write( "2(x^2+25)(x+3)(x^2-2x+10)
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