document.write( "Question 1191959: A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $67. A season ski pass costs $350. The skier would have to rent skis with either pass for $25 per day. How many days would the skier have to go skiing in order to make the season pass less expensive than the daily passes? \n" ); document.write( "

Algebra.Com's Answer #823849 by math_helper(2461) $\"\"$ $\"About$

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document.write( "Cost equation for daily pass:  \r
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document.write( "    C_daily = 67x + 25x = 92x,  where x = # days skied\r
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document.write( "Cost equation for season pass:
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document.write( "    C_season = 350 + 25x\r
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document.write( "We wish to find x such that C_season < C_daily\r
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document.write( "   350 + 25x < 92x
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document.write( "       350   < 67x\r
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document.write( "       350/67 < x    
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document.write( "        5.224 < x     \r
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document.write( "    x = 6 ski days\r
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document.write( "Sanity check...\r
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document.write( "#days skied     Daily pass cost     Season pass cost
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document.write( "    4             368                   450
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document.write( "    5             460                   475
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document.write( "    6             552                   500    <----  Season pass becomes cheaper\r
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document.write( "If you plot the two cost equations, the point where they cross is the point where the season pass becomes more cost effective (well, the nearest integer above where they cross).   \r
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document.write( "The green line represents the season pass cost equation:\r
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