document.write( "Question 1191968: Suppose a family drives an average rate of 60mi/h on the way to visit relatives and then at an average rate of 40mi/h on the way back. The return trip takes 1h longer than the trip there.\r
\n" ); document.write( "\n" ); document.write( "a. Let d be the distance in miles the family traveled to visit their relatives. How many hours did they take to drive there?\r
\n" ); document.write( "\n" ); document.write( "b. In terms of d, how many hours did it take to make the return trip?\r
\n" ); document.write( "\n" ); document.write( "c. Write and solve an equation to determine the distance the family traveled to see their relatives. What was the average rate for the entire trip?
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Algebra.Com's Answer #823835 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "             SPEED          TIME              DIST.\r\n" );
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document.write( "GOING          60           d/60                 d\r\n" );
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document.write( "RETURN         40           d/40                 d\r\n" );
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document.write( "DIFF.                         1\r\n" );
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\n" ); document.write( "\"d%2F40-d%2F60=1\"
\n" ); document.write( "Simplify and solve for d.
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