document.write( "Question 1191928: for a normal distribution if the value of mean is 70 and standard deviation is 15.75 find the points
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document.write( "(a) in which it contains 98% area between them
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document.write( "(b) in which it contains 95% area between them
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document.write( "(c) in which it contains 85% area between them
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document.write( "(d) in which 60% area between them
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Algebra.Com's Answer #823807 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your teacher is asking you to find the values of m and n such that \n" ); document.write( "P(m < X < n) = 0.98 \n" ); document.write( "The problem is that there are infinitely many solutions for m,n.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It's similar to how \n" ); document.write( "P(r < Z < s) = 0.98 \n" ); document.write( "also has infinitely many solutions for r,s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, if we were to use symmetry and say \n" ); document.write( "P(-k < Z < k) = 0.98 \n" ); document.write( "then there's exactly one solution for k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the duration of this solution, I'll assume that your teacher is using the P(-k < Z < k) method.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "98% of the area is in the main body leaving 100% - 98% = 2% in the two tails combined. \n" ); document.write( "Each tail would have (2%)/2 = 1% of the area. \n" ); document.write( "We're able to divide by two because of the mirror symmetry mentioned.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a table or calculator to find that P(Z < k) = 0.01 has a solution of roughly k = -2.327 \n" ); document.write( "Here's a useful calculator \n" ); document.write( "https://davidmlane.com/normal.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That k value leads to \n" ); document.write( "P(-2.327 < Z < 2.327) = 0.98 \n" ); document.write( "Meaning that about 98% of the area under the standard normal Z curve is between the z scores -2.327 and 2.327\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let's convert each mentioned z score into their corresponding raw score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll start with z = -2.327 \n" ); document.write( "z = (x-mu)/sigma \n" ); document.write( "z*sigma = x-mu \n" ); document.write( "x = mu+z*sigma \n" ); document.write( "x = 70+(-2.327)*15.75 \n" ); document.write( "x = 33.34975\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then repeat for z = 2.327 \n" ); document.write( "x = mu+z*sigma \n" ); document.write( "x = 70+2.327*15.75 \n" ); document.write( "x = 106.65025\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( "P(33.34975 < X < 106.65025) = 0.98 \n" ); document.write( "approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You'll follow similar steps for parts (b) through (d). \n" ); document.write( " \n" ); document.write( " |