document.write( "Question 1191929: for a normal distribution if the value of mean is 70 and standard deviation is 15.75 find the points
\n" ); document.write( "(a) in which it contains 98% area between them
\n" ); document.write( "(b) in which it contains 95% area between them
\n" ); document.write( "(c) in which it contains 85% area between them
\n" ); document.write( "(d) in which 60% area between them
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Algebra.Com's Answer #823802 by Boreal(15235)\"\" \"About 
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98% of the area between want z of 0.01 and 0.99 which is +/-2.326
\n" ); document.write( "95% of the area is z +/-1.96
\n" ); document.write( "85% of the area is between -0.075 and 0.925 for z of +/-1.44
\n" ); document.write( "60% of the area is between 0.2 and 0.8 for z of +/- 0.8416
\n" ); document.write( "z=(x-mean)/sd
\n" ); document.write( "2.326=(x-70)/15.75
\n" ); document.write( "x-70=36.63
\n" ); document.write( "x=106.63 and the other value is 33.37. (33.37, 106.63)
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\n" ); document.write( "the second one is mean+/-1.96*15.75=30.87 (39.13, 100.87)
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\n" ); document.write( "the third one is mean +/-22.68 (47.32, 92.68)
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\n" ); document.write( "the fourth one is mean +/-0.8416 =13.26 for (56.74, 83.26) \n" ); document.write( "
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