document.write( "Question 1191902: A line passes through (2,4) and perpendicular to the line 3x+4y-4=0. Find the equation of the line. \n" ); document.write( "
Algebra.Com's Answer #823746 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Anything of the form Ax+By+C = 0 will have Bx-Ay+D = 0 perpendicular to it.
\n" ); document.write( "Note the swap of A and B, and also the sign change.\r
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\n" ); document.write( "\n" ); document.write( "In the case of 3x+4y-4=0, we have
\n" ); document.write( "A = 3
\n" ); document.write( "B = 4
\n" ); document.write( "C = -4\r
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\n" ); document.write( "\n" ); document.write( "So Bx-Ay+D = 0 becomes 4x-3y+D = 0\r
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\n" ); document.write( "\n" ); document.write( "Plug in the coordinates of (x,y) = (2,4) and solve for D
\n" ); document.write( "4x-3y+D = 0
\n" ); document.write( "4(2)-3(4)+D = 0
\n" ); document.write( "8-12+D = 0
\n" ); document.write( "-4+D = 0
\n" ); document.write( "D = 4\r
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\n" ); document.write( "\n" ); document.write( "We go from 4x-3y+D = 0 to 4x-3y+4 = 0 which is one way to write the equation of the perpendicular line. Other formats are possible.
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