document.write( "Question 1191883: A movie theater has a seating capacity of 197. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. There are half as many adults as there are children. If the total ticket sales was $ 1430, How many children, students, and adults attended? \n" ); document.write( "

Algebra.Com's Answer #823735 by ikleyn(52776) $\"\"$ $\"About$

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\n" ); document.write( "A movie theater has a seating capacity of 197.
\n" ); document.write( "The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults.
\n" ); document.write( "There are half as many adults as there are children.
\n" ); document.write( "If the total ticket sales was $ 1430, How many children, students, and adults attended?
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document.write( "adults   = x\r\n" );
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document.write( "children = 2x\r\n" );
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document.write( "students = 197 - x - 2x = 197 - 3x\r\n" );
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document.write( "Total money equation (the revenue)\r\n" );
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document.write( "    12x + 5*(2x) + 7*(197-3x) = 1430\r\n" );
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document.write( "From the equation\r\n" );
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document.write( "    x =  = 51.\r\n" );
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document.write( "ANSWER.  adults: 51;  children: 2*51 = 102;  students: 197-3*51 = 44.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved (using one equation in one unknown).\r
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