document.write( "Question 1191884: A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 35% and the third contains 55%. They want to use all three solutions to obtain a mixture of 216 liters containing 30% acid, using 3 times as much of the 55% solution as the 35% solution. How many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #823733 by josgarithmetic(39617)\"\" \"About 
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document.write( "CONC. %           QTY VOLUME L        PURE\r\n" );
document.write( "  20               216-4v             0.2(216-4v)\r\n" );
document.write( "  35                 v                0.35v\r\n" );
document.write( "  55                3v                0.55*3v\r\n" );
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document.write( "  30               216           0.2(216-4v)+0.35v+0.55*3v\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"0.2%28216-4v%29%2B0.35v%2B0.55%2A3v=0.30%2A216\"
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