document.write( "Question 1191855: 25. A metallurgist decides to experiment with a new alloy by using iron
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document.write( "and nickel in the ratio 21:5 by mass and nickel and copper in the ratio 4:3 by mass. How many grams of each metal does the
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document.write( "metallurgist use to make 238 g of the alloy? \n" );
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Algebra.Com's Answer #823710 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Given: \n" ); document.write( "iron:nickel = 21:5 \n" ); document.write( "nickel:copper = 4:3 \n" ); document.write( "Write each ratio as an equivalent ratio so that the numbers representing nickel in both ratios are the same. \n" ); document.write( "iron:nickel = 84:20 \n" ); document.write( "nickel:copper = 20:15 \n" ); document.write( "Then \n" ); document.write( "iron = 84x \n" ); document.write( "nickel = 20x \n" ); document.write( "copper = 15x \n" ); document.write( "The total is to be 238g: \n" ); document.write( "84x+20x+15x = 238 \n" ); document.write( "119x = 238 \n" ); document.write( "x=2 \n" ); document.write( "ANSWERS: \n" ); document.write( "iron = 84x = 168g \n" ); document.write( "nickel = 20x = 40g \n" ); document.write( "copper = 15x = 30g \n" ); document.write( " \n" ); document.write( " |