document.write( "Question 1191817: The demand equation for a certain product is given by
\n" ); document.write( "p=100−0.045x, where
\n" ); document.write( "p is the unit price (in dollars) of the product and
\n" ); document.write( "x is the number of units produced. The total revenue obtained by producing and selling
\n" ); document.write( "x units is given by R=xp
\n" ); document.write( " .\r
\n" ); document.write( "\n" ); document.write( "Determine prices
\n" ); document.write( "p
\n" ); document.write( " that would yield a revenue of 5910 dollars.\r
\n" ); document.write( "\n" ); document.write( "Lowest such price =
\n" ); document.write( "
\n" ); document.write( "Highest such price = \n" ); document.write( "
Algebra.Com's Answer #823705 by ankor@dixie-net.com(22740)\"\" \"About 
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The demand equation for a certain product is given by p=100−0.045x, where p is the unit price (in dollars) of the product and x is the number of units produced.
\n" ); document.write( " The total revenue obtained by producing and selling
\n" ); document.write( "x units is given by R=xp.
\n" ); document.write( "Determine prices p that would yield a revenue of 5910 dollars.
\n" ); document.write( "xp = 5910
\n" ); document.write( "replace p with 100-.045x, from the given equation
\n" ); document.write( "x(100-.045x) = 5910
\n" ); document.write( "100x - 045x^2 = 5910
\n" ); document.write( "arrange as a quadratic equation
\n" ); document.write( "-.045x^2 + 100x - 5910 = 0
\n" ); document.write( "Using the quadratic equation I got two solutions
\n" ); document.write( "x = 2161.46 ~ 2162 units
\n" ); document.write( "x = 60.76 ~ 61 units
\n" ); document.write( ":
\n" ); document.write( "Lowest such price = 100 - .045(2162) = $2.71
\n" ); document.write( ":
\n" ); document.write( "Highest such price = 100 - .045(62) = $97.21 \n" ); document.write( "
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