document.write( "Question 1191852: Michael and Janet are 10 years apart in age. In 24 months Michael will be twice as old as Janet. How old is Janet now? \n" ); document.write( "
Algebra.Com's Answer #823702 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "j = Janet's age currently
\n" ); document.write( "j+10 = Michael's age currently
\n" ); document.write( "Whatever number j is, add 10 to get Michael's age.
\n" ); document.write( "The two are always separated by a gap of 10 years.\r
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\n" ); document.write( "\n" ); document.write( "12 months = 1 year
\n" ); document.write( "2*12 months = 2*1 year
\n" ); document.write( "24 months = 2 years\r
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\n" ); document.write( "\n" ); document.write( "In 2 years time, we have these future ages
\n" ); document.write( "Janet = j+2
\n" ); document.write( "Michael = (j+10)+2 = j+12\r
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\n" ); document.write( "\n" ); document.write( "At this future point in time, Michael is twice as old as Janet
\n" ); document.write( "Michael's future age = 2*(Janet's future age)
\n" ); document.write( "j+12 = 2*(j+2)
\n" ); document.write( "j+12 = 2j+4
\n" ); document.write( "12-4 = 2j-j
\n" ); document.write( "8 = j
\n" ); document.write( "j = 8
\n" ); document.write( "Janet is currently 8 years old
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\n" ); document.write( "\n" ); document.write( "Michael is currently j+10 = 8+10 = 18 years old.\r
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\n" ); document.write( "\n" ); document.write( "In 2 years, we have these future ages
\n" ); document.write( "Janet = 8+2 = 10
\n" ); document.write( "Michael = 18+2 = 20
\n" ); document.write( "we see that Michael is indeed twice as old as Janet at this point (20 = 10*2).
\n" ); document.write( "The answer has been confirmed.\r
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\n" ); document.write( "Here's another approach:\r
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\n" ); document.write( "\n" ); document.write( "j = Janet's age 2 years into the future
\n" ); document.write( "j+10 = Michael's age 2 years into the future\r
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\n" ); document.write( "\n" ); document.write( "Michael's future age = 2*(Janet's future age)
\n" ); document.write( "j+10 = 2*(j)
\n" ); document.write( "j+10 = 2j
\n" ); document.write( "10 = 2j-j
\n" ); document.write( "10 = j
\n" ); document.write( "j = 10
\n" ); document.write( "This says Janet will be 10 years old when we fast forward two years into the future.
\n" ); document.write( "Rewinding two years back, to get to the present day, gets us to 10-2 = 8 as the final answer.\r
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\n" ); document.write( "\n" ); document.write( "This method effectively follows the same idea as the previous section.
\n" ); document.write( "Except this time, the frame of reference starts off based in the future at first before rewinding back. \r
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\n" ); document.write( "\n" ); document.write( "Answer: 8 years old
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