document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16937>Question 16937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help: 9(11-k)=3(3k-9) The answer is 10 i think and im not sure how to get there. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8237 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9(11-k)=3(3k-9)<BR>\n" );
document.write( "9*11-9k=3*3k-3*9<BR>\n" );
document.write( "99-9k=9k-27<BR>\n" );
document.write( "9k-27=99-9k<BR>\n" );
document.write( "9k+9k=99+27<BR>\n" );
document.write( "18k=126<BR>\n" );
document.write( "k=126/18=7<BR>\n" );
document.write( "k=7...verification ..substitute k=7 in 9(11-k)=3(3k-9)<BR>\n" );
document.write( "9(11-7)=9*4=36=3(3*7-9)=3(21-9)=3*12=36....ok. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );