document.write( "Question 1191833: Let U = {q, r, s, t, u, v, w, x, y, z}
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document.write( " A = {q, s, u, w, y}
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document.write( " B = {q, s, y, z}
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document.write( " C = {v, w, x, y, z}.
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document.write( "Determine the following.\r
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document.write( "A ∩ B' \n" );
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Algebra.Com's Answer #823690 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "A ∩ B'\r\n" ); document.write( "\r\n" ); document.write( "Substitute {q, s, u, w, y} for A and {q, s, y, z} for B:\r\n" ); document.write( "\r\n" ); document.write( "{q, s, u, w, y} ∩ {q, s, y, z}'\r\n" ); document.write( "\r\n" ); document.write( "Take care of the \" ' \" first. That means \"complement\", which means\r\n" ); document.write( "to take all the elements of U that are not members of {q, s, y, z}.\r\n" ); document.write( "So in place of {q, s, y, z}' we write {r, t, u, v, w, x}.\r\n" ); document.write( "\r\n" ); document.write( "{q, s, u, w, y} ∩ {r, t, u, v, w, x}\r\n" ); document.write( "\r\n" ); document.write( "Now \" ∩ \" (intersection) says to take ONLY the elements which are\r\n" ); document.write( "IN COMMON to both sets. That is, only those elements which are \r\n" ); document.write( "contained in both sets on the left and right of ∩. There are only \r\n" ); document.write( "two:\r\n" ); document.write( "\r\n" ); document.write( "{u, w} <--answer\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |