document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191796>Question 1191796</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the function. \r<BR>\n" );
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document.write( "f(x)=3/x+9\r<BR>\n" );
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document.write( "Not sure what to do. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823634 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the domain is all real values of x that lead to a real value of f(x).<BR>\n" );
document.write( "you have f(x) = 3/(x+9)<BR>\n" );
document.write( "since (x+9) is in the denominator, then the denominator will be equal to 0 when x = -9.<BR>\n" );
document.write( "the value of f(x) = 3/(x+9) is not defined when the denominator is equal to 0.<BR>\n" );
document.write( "the domain of the function is therefore all values of x except at x = -9.<BR>\n" );
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