document.write( "Question 1191782: Each of the 40 boys in a group plays at least one of the two games: Badminton(B) and
\n" ); document.write( "Football(F). 21 play Badminton and 28 play Football. Let the number of boys who play both
\n" ); document.write( "Badminton and Football be x.
\n" ); document.write( "a. Draw a clearly labelled Venn diagram to illustrate this information.
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\n" ); document.write( "ii.The number of boys who play only Badminton but not Football.
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Algebra.Com's Answer #823617 by ikleyn(52855)\"\" \"About 
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\n" ); document.write( "Each of the 40 boys in a group plays at least one of the two games: Badminton(B) and
\n" ); document.write( "Football(F). 21 play Badminton and 28 play Football. Let the number of boys who play both
\n" ); document.write( "Badminton and Football be x.
\n" ); document.write( "a. Draw a clearly labelled Venn diagram to illustrate this information.
\n" ); document.write( "b.Hence, find
\n" ); document.write( "i.The value of x,
\n" ); document.write( "ii.The number of boys who play only Badminton but not Football.
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document.write( "Use the fundamental formula for the union of two subsets B and F of the given finite set\r\n" );
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document.write( "    n(B U F) = n(B) + n(F) - n(B ∩ F).\r\n" );
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document.write( "In your case,  n(B U F) = 40,  since each of the 40 boys in a group plays at least one of the two games,\r\n" );
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document.write( "and  x = n(B ∩ F).\r\n" );
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document.write( "Therefore,  40 = 21 + 28 - x,  which implies\r\n" );
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document.write( "    x = 21 + 28 - 40 = 49 - 40 = 9.\r\n" );
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document.write( "Thus 9 boys play both sports.\r\n" );
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document.write( "The number of those who play only Badminton, is  21 - 9 = 12.\r\n" );
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document.write( "To get it, we should subtract those who play both sports from those who play Badminton.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar  (and different)  solved problems,  look into the lesson\r
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