document.write( "Question 1191708: The equation of a curve is y = x^2/(x+2). The tangent to the curve at the point where x = -3 meets the
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document.write( "y- axis at M. The normal to the curve at the point where x = -3 meets the x - axis at N. Find the
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document.write( "area of the triangle MNO, where O is the origin. \n" );
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Algebra.Com's Answer #823562 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! We first locate the precise point on the curve where the tangent and normal lines are:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the point we’re looking for is ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation of tangent at \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so M( \n" ); document.write( "\n" ); document.write( "So the slope of the tangent line is \n" ); document.write( "Equation of normal at \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "N( \n" ); document.write( "\n" ); document.write( "In right triangle \n" ); document.write( "\n" ); document.write( "then the area \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |