document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191704>Question 1191704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to Masterfoods, the company that manufactures M&Ms, 12% of peanut M&Ms are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. Assume that selecting multiple M&Ms are independent events. (Round your answers to three decimal places, for example 0.123)\r<BR>\n" );
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document.write( "Compute the probability that a randomly selected peanut M&M is not green.\r<BR>\n" );
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document.write( "Compute the probability that three randomly selected peanut M&Ms are all green.\r<BR>\n" );
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document.write( "If you randomly select four peanut M&Ms, compute the probability that none of them are red. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823506 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p(not green) is 1-p(green)=0.85<BR>\n" );
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document.write( "all three are green is 0.15^3=0.003375 or 0.003. Sorry, I was still thinking of complement. <BR>\n" );
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document.write( "none red is 0.88^4=0.5997 or 0.600. <BR>\n" );
document.write( "There is an 88% chance it won't be red.  </SPAN>\n" );
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