document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191699>Question 1191699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invested P140,000. Part of his capital was invested at 11% and the rest at 9%. If the total income of the investments is P13,900, how much was invested at each rate? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823500 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a non-traditional non-algebraic way to solve any two-part \"mixture\" problem like this.<br><BR>\n" );
document.write( "All P140,000 invested at 9% would yield P12,600 interest; all at 11% would yield P15,400 interest; the actual interest was P13,900.<BR>\n" );
document.write( "Consider the three interest amounts 12600, 13900, and 15400 on a number line and observe/calculate that 13900 is 1300/2800 = 13/28 of the way from 12600 to 15400.<BR>\n" );
document.write( "That means 13/28 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "(13/28)(140000)=13(5000)=65000<br><BR>\n" );
document.write( "ANSWER: P65000 at 11%; P75000 at 9%<br><BR>\n" );
document.write( "CHECK: .11(65000)+.09(75000)=7150+6750=13900<br><BR>\n" );
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